Base | Representation |
---|---|
bin | 11100011110011010011110… |
… | …011110011101110101001011 |
3 | 121102102101020102222001120110 |
4 | 130132122132132131311023 |
5 | 112403323411143002103 |
6 | 1122204150510525403 |
7 | 35243644600160106 |
oct | 3436323636356513 |
9 | 542371212861513 |
10 | 125235315203403 |
11 | 369a3aa9610989 |
12 | 12067539806863 |
13 | 54b5841125962 |
14 | 22cd5c8c1373d |
15 | e729d0890403 |
hex | 71e69e79dd4b |
125235315203403 has 16 divisors (see below), whose sum is σ = 176807223204480. Its totient is φ = 78577054517376.
The previous prime is 125235315203393. The next prime is 125235315203429. The reversal of 125235315203403 is 304302513532521.
It is not a de Polignac number, because 125235315203403 - 214 = 125235315187019 is a prime.
It is not an unprimeable number, because it can be changed into a prime (125235315203903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28672125 + ... + 32749982.
It is an arithmetic number, because the mean of its divisors is an integer number (11050451450280).
Almost surely, 2125235315203403 is an apocalyptic number.
125235315203403 is a deficient number, since it is larger than the sum of its proper divisors (51571908001077).
125235315203403 is a wasteful number, since it uses less digits than its factorization.
125235315203403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61462106.
The product of its (nonzero) digits is 324000, while the sum is 39.
Adding to 125235315203403 its reverse (304302513532521), we get a palindrome (429537828735924).
The spelling of 125235315203403 in words is "one hundred twenty-five trillion, two hundred thirty-five billion, three hundred fifteen million, two hundred three thousand, four hundred three".
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