Base | Representation |
---|---|
bin | 10010001110011011110… |
… | …110111001011010011011 |
3 | 11102201210102021120200021 |
4 | 102032123312321122123 |
5 | 131010004241430210 |
6 | 2355211233251311 |
7 | 156325613154436 |
oct | 22163366713233 |
9 | 4381712246607 |
10 | 1252450342555 |
11 | 443185626835 |
12 | 182897103b37 |
13 | 9114abbb669 |
14 | 4489446081d |
15 | 228a474cbda |
hex | 1239bdb969b |
1252450342555 has 16 divisors (see below), whose sum is σ = 1508430147840. Its totient is φ = 998301292128.
The previous prime is 1252450342457. The next prime is 1252450342607. The reversal of 1252450342555 is 5552430542521.
It is a cyclic number.
It is not a de Polignac number, because 1252450342555 - 29 = 1252450342043 is a prime.
It is a super-3 number, since 3×12524503425553 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13025284 + ... + 13121086.
It is an arithmetic number, because the mean of its divisors is an integer number (94276884240).
Almost surely, 21252450342555 is an apocalyptic number.
1252450342555 is a deficient number, since it is larger than the sum of its proper divisors (255979805285).
1252450342555 is an equidigital number, since it uses as much as digits as its factorization.
1252450342555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105330.
The product of its (nonzero) digits is 1200000, while the sum is 43.
The spelling of 1252450342555 in words is "one trillion, two hundred fifty-two billion, four hundred fifty million, three hundred forty-two thousand, five hundred fifty-five".
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