Base | Representation |
---|---|
bin | 10010001110100000000… |
… | …001011011101110111011 |
3 | 11102201222021202101111122 |
4 | 102032200001123232323 |
5 | 131010130133312220 |
6 | 2355222211015455 |
7 | 156330422102561 |
oct | 22164001335673 |
9 | 4381867671448 |
10 | 1252520213435 |
11 | 443211009867 |
12 | 1828b659a58b |
13 | 9115c51348a |
14 | 4489d84ba31 |
15 | 228aa950425 |
hex | 123a005bbbb |
1252520213435 has 4 divisors (see below), whose sum is σ = 1503024256128. Its totient is φ = 1002016170744.
The previous prime is 1252520213431. The next prime is 1252520213447. The reversal of 1252520213435 is 5343120252521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1252520213435 - 22 = 1252520213431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1252520213395 and 1252520213404.
It is not an unprimeable number, because it can be changed into a prime (1252520213431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125252021339 + ... + 125252021348.
It is an arithmetic number, because the mean of its divisors is an integer number (375756064032).
Almost surely, 21252520213435 is an apocalyptic number.
1252520213435 is a deficient number, since it is larger than the sum of its proper divisors (250504042693).
1252520213435 is an equidigital number, since it uses as much as digits as its factorization.
1252520213435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 250504042692.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 1252520213435 its reverse (5343120252521), we get a palindrome (6595640465956).
The spelling of 1252520213435 in words is "one trillion, two hundred fifty-two billion, five hundred twenty million, two hundred thirteen thousand, four hundred thirty-five".
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