Base | Representation |
---|---|
bin | 111010010110010011… |
… | …0110011101110100001 |
3 | 102222102112121120122111 |
4 | 1310230212303232201 |
5 | 4023104410004213 |
6 | 133321345435321 |
7 | 12024053005636 |
oct | 1645446635641 |
9 | 388375546574 |
10 | 125302422433 |
11 | 4915aa50621 |
12 | 2034b63bb41 |
13 | ba7b8b1536 |
14 | 60c964c18d |
15 | 33d5748a3d |
hex | 1d2c9b3ba1 |
125302422433 has 4 divisors (see below), whose sum is σ = 125864316928. Its totient is φ = 124740527940.
The previous prime is 125302422379. The next prime is 125302422451. The reversal of 125302422433 is 334224203521.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 125302422433 - 221 = 125300325281 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 125302422395 and 125302422404.
It is not an unprimeable number, because it can be changed into a prime (125302432433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 280946913 + ... + 280947358.
It is an arithmetic number, because the mean of its divisors is an integer number (31466079232).
Almost surely, 2125302422433 is an apocalyptic number.
It is an amenable number.
125302422433 is a deficient number, since it is larger than the sum of its proper divisors (561894495).
125302422433 is an equidigital number, since it uses as much as digits as its factorization.
125302422433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 561894494.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 125302422433 its reverse (334224203521), we get a palindrome (459526625954).
The spelling of 125302422433 in words is "one hundred twenty-five billion, three hundred two million, four hundred twenty-two thousand, four hundred thirty-three".
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