Base | Representation |
---|---|
bin | 11100011111011011101010… |
… | …101100110110111011000001 |
3 | 121102200001220202011001002121 |
4 | 130133123222230312323001 |
5 | 112411000240230140340 |
6 | 1122300244421444241 |
7 | 35252003324102566 |
oct | 3437335254667301 |
9 | 542601822131077 |
10 | 125305313521345 |
11 | 36a20759864221 |
12 | 12079013b70681 |
13 | 54bc3181017b9 |
14 | 22d2b4950c86d |
15 | e7472ac6c94a |
hex | 71f6eab36ec1 |
125305313521345 has 4 divisors (see below), whose sum is σ = 150366376225620. Its totient is φ = 100244250817072.
The previous prime is 125305313521321. The next prime is 125305313521351. The reversal of 125305313521345 is 543125313503521.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 66779034360336 + 58526279161009 = 8171844^2 + 7650247^2 .
It is a cyclic number.
It is not a de Polignac number, because 125305313521345 - 25 = 125305313521313 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12530531352130 + ... + 12530531352139.
It is an arithmetic number, because the mean of its divisors is an integer number (37591594056405).
Almost surely, 2125305313521345 is an apocalyptic number.
It is an amenable number.
125305313521345 is a deficient number, since it is larger than the sum of its proper divisors (25061062704275).
125305313521345 is an equidigital number, since it uses as much as digits as its factorization.
125305313521345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25061062704274.
The product of its (nonzero) digits is 810000, while the sum is 43.
The spelling of 125305313521345 in words is "one hundred twenty-five trillion, three hundred five billion, three hundred thirteen million, five hundred twenty-one thousand, three hundred forty-five".
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