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125305313521345 = 525061062704269
BaseRepresentation
bin11100011111011011101010…
…101100110110111011000001
3121102200001220202011001002121
4130133123222230312323001
5112411000240230140340
61122300244421444241
735252003324102566
oct3437335254667301
9542601822131077
10125305313521345
1136a20759864221
1212079013b70681
1354bc3181017b9
1422d2b4950c86d
15e7472ac6c94a
hex71f6eab36ec1

125305313521345 has 4 divisors (see below), whose sum is σ = 150366376225620. Its totient is φ = 100244250817072.

The previous prime is 125305313521321. The next prime is 125305313521351. The reversal of 125305313521345 is 543125313503521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 66779034360336 + 58526279161009 = 8171844^2 + 7650247^2 .

It is a cyclic number.

It is not a de Polignac number, because 125305313521345 - 25 = 125305313521313 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12530531352130 + ... + 12530531352139.

It is an arithmetic number, because the mean of its divisors is an integer number (37591594056405).

Almost surely, 2125305313521345 is an apocalyptic number.

It is an amenable number.

125305313521345 is a deficient number, since it is larger than the sum of its proper divisors (25061062704275).

125305313521345 is an equidigital number, since it uses as much as digits as its factorization.

125305313521345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25061062704274.

The product of its (nonzero) digits is 810000, while the sum is 43.

The spelling of 125305313521345 in words is "one hundred twenty-five trillion, three hundred five billion, three hundred thirteen million, five hundred twenty-one thousand, three hundred forty-five".

Divisors: 1 5 25061062704269 125305313521345