Base | Representation |
---|---|
bin | 10010001111000100011… |
… | …000111000110001001011 |
3 | 11102210112210211002210120 |
4 | 102033010120320301023 |
5 | 131012402331411301 |
6 | 2355402524114323 |
7 | 156351511103502 |
oct | 22170430706113 |
9 | 4383483732716 |
10 | 1253130341451 |
11 | 4434a4454a9a |
12 | 182a469959a3 |
13 | 91228a46c81 |
14 | 4491a8ad839 |
15 | 228e42bde36 |
hex | 123c4638c4b |
1253130341451 has 16 divisors (see below), whose sum is σ = 1675328196096. Its totient is φ = 833179054496.
The previous prime is 1253130341423. The next prime is 1253130341479. The reversal of 1253130341451 is 1541430313521.
It is an interprime number because it is at equal distance from previous prime (1253130341423) and next prime (1253130341479).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1253130341451 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1253130341951) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1526641 + ... + 2199293.
It is an arithmetic number, because the mean of its divisors is an integer number (104708012256).
Almost surely, 21253130341451 is an apocalyptic number.
1253130341451 is a deficient number, since it is larger than the sum of its proper divisors (422197854645).
1253130341451 is a wasteful number, since it uses less digits than its factorization.
1253130341451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 674322.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 1253130341451 its reverse (1541430313521), we get a palindrome (2794560654972).
The spelling of 1253130341451 in words is "one trillion, two hundred fifty-three billion, one hundred thirty million, three hundred forty-one thousand, four hundred fifty-one".
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