12531643339737 has 4 divisors (see below), whose sum is σ = 16708857786320. Its totient is φ = 8354428893156.

The previous prime is 12531643339679. The next prime is 12531643339783. The reversal of 12531643339737 is 73793334613521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12531643339737 - 2³⁶ = 12462923863001 is a prime.

It is a super-2 number, since 2×12531643339737² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12531643739737) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2088607223287 + ... + 2088607223292.

It is an arithmetic number, because the mean of its divisors is an integer number (4177214446580).

Almost surely, 2^{12531643339737} is an apocalyptic number.

It is an amenable number.

12531643339737 is a deficient number, since it is larger than the sum of its proper divisors (4177214446583).

12531643339737 is an equidigital number, since it uses as much as digits as its factorization.

12531643339737 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4177214446582.

The product of its digits is 25719120, while the sum is 57.

The spelling of 12531643339737 in words is "twelve trillion, five hundred thirty-one billion, six hundred forty-three million, three hundred thirty-nine thousand, seven hundred thirty-seven".