12532400315441 has 4 divisors (see below), whose sum is σ = 12560947924800. Its totient is φ = 12503852706084.

The previous prime is 12532400315423. The next prime is 12532400315453. The reversal of 12532400315441 is 14451300423521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12532400315441 is a prime.

It is a super-3 number, since 3×12532400315441³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12532400315411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14273804021 + ... + 14273804898.

It is an arithmetic number, because the mean of its divisors is an integer number (3140236981200).

Almost surely, 2^{12532400315441} is an apocalyptic number.

It is an amenable number.

12532400315441 is a deficient number, since it is larger than the sum of its proper divisors (28547609359).

12532400315441 is an equidigital number, since it uses as much as digits as its factorization.

12532400315441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28547609358.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 12532400315441 its reverse (14451300423521), we get a palindrome (26983700738962).

The spelling of 12532400315441 in words is "twelve trillion, five hundred thirty-two billion, four hundred million, three hundred fifteen thousand, four hundred forty-one".