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12533113001 = 51712423731
BaseRepresentation
bin10111010110000100…
…00010000010101001
31012100110021002220102
423223002002002221
5201131434104001
65431352035145
7622403463023
oct135302020251
935313232812
1012533113001
115351685332
122519392ab5
1312497417c6
1486c753013
154d5479e6b
hex2eb0820a9

12533113001 has 4 divisors (see below), whose sum is σ = 12535541904. Its totient is φ = 12530684100.

The previous prime is 12533112973. The next prime is 12533113007. The reversal of 12533113001 is 10031133521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10031133521 = 41549241429.

It is a cyclic number.

It is not a de Polignac number, because 12533113001 - 230 = 11459371177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12533113007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1206695 + ... + 1217036.

It is an arithmetic number, because the mean of its divisors is an integer number (3133885476).

Almost surely, 212533113001 is an apocalyptic number.

It is an amenable number.

12533113001 is a deficient number, since it is larger than the sum of its proper divisors (2428903).

12533113001 is an equidigital number, since it uses as much as digits as its factorization.

12533113001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2428902.

The product of its (nonzero) digits is 270, while the sum is 20.

Adding to 12533113001 its reverse (10031133521), we get a palindrome (22564246522).

The spelling of 12533113001 in words is "twelve billion, five hundred thirty-three million, one hundred thirteen thousand, one".

Divisors: 1 5171 2423731 12533113001