125354343324003 has 4 divisors (see below), whose sum is σ = 167139124432008. Its totient is φ = 83569562216000.

The previous prime is 125354343323903. The next prime is 125354343324079. The reversal of 125354343324003 is 300423343453521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 125354343324003 - 2²⁶ = 125354276215139 is a prime.

It is a super-3 number, since 3×125354343324003³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (125354343344003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20892390553998 + ... + 20892390554003.

It is an arithmetic number, because the mean of its divisors is an integer number (41784781108002).

Almost surely, 2^{125354343324003} is an apocalyptic number.

125354343324003 is a deficient number, since it is larger than the sum of its proper divisors (41784781108005).

125354343324003 is an equidigital number, since it uses as much as digits as its factorization.

125354343324003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41784781108004.

The product of its (nonzero) digits is 1555200, while the sum is 42.

Adding to 125354343324003 its reverse (300423343453521), we get a palindrome (425777686777524).

The spelling of 125354343324003 in words is "one hundred twenty-five trillion, three hundred fifty-four billion, three hundred forty-three million, three hundred twenty-four thousand, three".