Base | Representation |
---|---|
bin | 111010011000000111… |
… | …1100100101011010011 |
3 | 102222120210102121110221 |
4 | 1310300033210223103 |
5 | 4023221020042324 |
6 | 133331405333511 |
7 | 12025423442464 |
oct | 1646017445323 |
9 | 388523377427 |
10 | 125363440339 |
11 | 49191437245 |
12 | 20367b67297 |
13 | ba8b4268c7 |
14 | 60d37b2d6b |
15 | 33dac9d0e4 |
hex | 1d303e4ad3 |
125363440339 has 4 divisors (see below), whose sum is σ = 125369376856. Its totient is φ = 125357503824.
The previous prime is 125363440331. The next prime is 125363440351. The reversal of 125363440339 is 933044363521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 125363440339 - 23 = 125363440331 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 125363440295 and 125363440304.
It is not an unprimeable number, because it can be changed into a prime (125363440331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2936469 + ... + 2978854.
It is an arithmetic number, because the mean of its divisors is an integer number (31342344214).
Almost surely, 2125363440339 is an apocalyptic number.
125363440339 is a deficient number, since it is larger than the sum of its proper divisors (5936517).
125363440339 is an equidigital number, since it uses as much as digits as its factorization.
125363440339 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5936516.
The product of its (nonzero) digits is 699840, while the sum is 43.
The spelling of 125363440339 in words is "one hundred twenty-five billion, three hundred sixty-three million, four hundred forty thousand, three hundred thirty-nine".
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