1254010540513 has 4 divisors (see below), whose sum is σ = 1254636608688. Its totient is φ = 1253384472340.

The previous prime is 1254010540501. The next prime is 1254010540547. The reversal of 1254010540513 is 3150450104521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1254010540513 - 2⁵ = 1254010540481 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1254010540553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 313031083 + ... + 313035088.

It is an arithmetic number, because the mean of its divisors is an integer number (313659152172).

Almost surely, 2^{1254010540513} is an apocalyptic number.

It is an amenable number.

1254010540513 is a deficient number, since it is larger than the sum of its proper divisors (626068175).

1254010540513 is an equidigital number, since it uses as much as digits as its factorization.

1254010540513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 626068174.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 1254010540513 in words is "one trillion, two hundred fifty-four billion, ten million, five hundred forty thousand, five hundred thirteen".