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125422115433 = 361685366751
BaseRepresentation
bin111010011001110111…
…1011001101001101001
3102222201212211121120120
41310303233121221221
54023331030143213
6133341303113453
712030035251056
oct1646357315151
9388655747516
10125422115433
114921157275a
1220383742889
13ba9a62b7b4
1460db4c802d
1533e0edd423
hex1d33bd9a69

125422115433 has 8 divisors (see below), whose sum is σ = 169970954496. Its totient is φ = 82244010000.

The previous prime is 125422115417. The next prime is 125422115501. The reversal of 125422115433 is 334511224521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 125422115433 - 24 = 125422115417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 125422115394 and 125422115403.

It is not an unprimeable number, because it can be changed into a prime (125422115233) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 342683193 + ... + 342683558.

It is an arithmetic number, because the mean of its divisors is an integer number (21246369312).

Almost surely, 2125422115433 is an apocalyptic number.

It is an amenable number.

125422115433 is a deficient number, since it is larger than the sum of its proper divisors (44548839063).

125422115433 is an equidigital number, since it uses as much as digits as its factorization.

125422115433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 685366815.

The product of its digits is 28800, while the sum is 33.

Adding to 125422115433 its reverse (334511224521), we get a palindrome (459933339954).

The spelling of 125422115433 in words is "one hundred twenty-five billion, four hundred twenty-two million, one hundred fifteen thousand, four hundred thirty-three".

Divisors: 1 3 61 183 685366751 2056100253 41807371811 125422115433