Base | Representation |
---|---|
bin | 1011011010000111111000… |
… | …1010101111101100110011 |
3 | 1122102010202121000212201120 |
4 | 2312201332022233230303 |
5 | 3121002411320002410 |
6 | 42402211305233323 |
7 | 2433142446304452 |
oct | 266417612575463 |
9 | 48363677025646 |
10 | 12543421250355 |
11 | 3aa66a9320376 |
12 | 14a6bba492843 |
13 | 6ccabb6462b8 |
14 | 31516790cb99 |
15 | 16b43aa8e570 |
hex | b687e2afb33 |
12543421250355 has 16 divisors (see below), whose sum is σ = 20074505300640. Its totient is φ = 6688147566848.
The previous prime is 12543421250341. The next prime is 12543421250369. The reversal of 12543421250355 is 55305212434521.
It is an interprime number because it is at equal distance from previous prime (12543421250341) and next prime (12543421250369).
It is a cyclic number.
It is not a de Polignac number, because 12543421250355 - 25 = 12543421250323 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 104756922 + ... + 104876591.
It is an arithmetic number, because the mean of its divisors is an integer number (1254656581290).
Almost surely, 212543421250355 is an apocalyptic number.
12543421250355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12543421250355 is a deficient number, since it is larger than the sum of its proper divisors (7531084050285).
12543421250355 is a wasteful number, since it uses less digits than its factorization.
12543421250355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 209637510.
The product of its (nonzero) digits is 720000, while the sum is 42.
Adding to 12543421250355 its reverse (55305212434521), we get a palindrome (67848633684876).
The spelling of 12543421250355 in words is "twelve trillion, five hundred forty-three billion, four hundred twenty-one million, two hundred fifty thousand, three hundred fifty-five".
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