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125439113 = 314046423
BaseRepresentation
bin1110111101000…
…00110010001001
322202000222010002
413132200302021
5224103022423
620240332345
73052133462
oct736406211
9282028102
10125439113
1164897298
12360140b5
131ccac837
1412933d69
15b02c228
hex77a0c89

125439113 has 4 divisors (see below), whose sum is σ = 129485568. Its totient is φ = 121392660.

The previous prime is 125439109. The next prime is 125439137. The reversal of 125439113 is 311934521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 125439113 - 22 = 125439109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (125439163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2023181 + ... + 2023242.

It is an arithmetic number, because the mean of its divisors is an integer number (32371392).

Almost surely, 2125439113 is an apocalyptic number.

It is an amenable number.

125439113 is a deficient number, since it is larger than the sum of its proper divisors (4046455).

125439113 is an equidigital number, since it uses as much as digits as its factorization.

125439113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4046454.

The product of its digits is 3240, while the sum is 29.

The square root of 125439113 is about 11199.9604017157. The cubic root of 125439113 is about 500.5847997518.

The spelling of 125439113 in words is "one hundred twenty-five million, four hundred thirty-nine thousand, one hundred thirteen".

Divisors: 1 31 4046423 125439113