Base | Representation |
---|---|
bin | 10111010111010110… |
… | …10101011101011001 |
3 | 1012101012122012100201 |
4 | 23223223111131121 |
5 | 201142222043231 |
6 | 5432420102201 |
7 | 622564506634 |
oct | 135353253531 |
9 | 35335565321 |
10 | 12543940441 |
11 | 535780012a |
12 | 2520b34961 |
13 | 124ba62b86 |
14 | 86dd70c1b |
15 | 4d63b8161 |
hex | 2ebad5759 |
12543940441 has 4 divisors (see below), whose sum is σ = 12548784384. Its totient is φ = 12539096500.
The previous prime is 12543940427. The next prime is 12543940477. The reversal of 12543940441 is 14404934521.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12543940441 - 29 = 12543939929 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12543940441.
It is not an unprimeable number, because it can be changed into a prime (12543940741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2418085 + ... + 2423266.
It is an arithmetic number, because the mean of its divisors is an integer number (3137196096).
Almost surely, 212543940441 is an apocalyptic number.
It is an amenable number.
12543940441 is a deficient number, since it is larger than the sum of its proper divisors (4843943).
12543940441 is an equidigital number, since it uses as much as digits as its factorization.
12543940441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4843942.
The product of its (nonzero) digits is 69120, while the sum is 37.
The spelling of 12543940441 in words is "twelve billion, five hundred forty-three million, nine hundred forty thousand, four hundred forty-one".
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