12544130005321 has 4 divisors (see below), whose sum is σ = 13282020005652. Its totient is φ = 11806240004992.

The previous prime is 12544130005301. The next prime is 12544130005333. The reversal of 12544130005321 is 12350003144521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6999141156921 + 5544988848400 = 2645589^2 + 2354780^2 .

It is not a de Polignac number, because 12544130005321 - 2¹⁵ = 12544129972553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12544130005301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 368945000140 + ... + 368945000173.

It is an arithmetic number, because the mean of its divisors is an integer number (3320505001413).

Almost surely, 2^{12544130005321} is an apocalyptic number.

It is an amenable number.

12544130005321 is a deficient number, since it is larger than the sum of its proper divisors (737890000331).

12544130005321 is an equidigital number, since it uses as much as digits as its factorization.

12544130005321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 737890000330.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 12544130005321 its reverse (12350003144521), we get a palindrome (24894133149842).

The spelling of 12544130005321 in words is "twelve trillion, five hundred forty-four billion, one hundred thirty million, five thousand, three hundred twenty-one".