Base | Representation |
---|---|
bin | 10111010111111000… |
… | …00111101110101011 |
3 | 1012101111220202022110 |
4 | 23223330013232223 |
5 | 201144333400101 |
6 | 5433054253403 |
7 | 622650064350 |
oct | 135374075653 |
9 | 35344822273 |
10 | 12548340651 |
11 | 535a236070 |
12 | 25224b7263 |
13 | 124c943952 |
14 | 870798627 |
15 | 4d6986cd6 |
hex | 2ebf07bab |
12548340651 has 16 divisors (see below), whose sum is σ = 20859579648. Its totient is φ = 6518618400.
The previous prime is 12548340643. The next prime is 12548340659. The reversal of 12548340651 is 15604384521.
It is an interprime number because it is at equal distance from previous prime (12548340643) and next prime (12548340659).
It is not a de Polignac number, because 12548340651 - 23 = 12548340643 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12548340659) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27160680 + ... + 27161141.
It is an arithmetic number, because the mean of its divisors is an integer number (1303723728).
Almost surely, 212548340651 is an apocalyptic number.
12548340651 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
12548340651 is a deficient number, since it is larger than the sum of its proper divisors (8311238997).
12548340651 is a wasteful number, since it uses less digits than its factorization.
12548340651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54321842.
The product of its (nonzero) digits is 115200, while the sum is 39.
The spelling of 12548340651 in words is "twelve billion, five hundred forty-eight million, three hundred forty thousand, six hundred fifty-one".
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