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12550144115 = 52510028823
BaseRepresentation
bin10111011000000110…
…00000000001110011
31012101122022101012102
423230003000001303
5201200314102430
65433201051015
7623001315305
oct135403000163
935348271172
1012550144115
115360258033
122523026a6b
1312501257a2
14870b07975
154d6be1345
hex2ec0c0073

12550144115 has 4 divisors (see below), whose sum is σ = 15060172944. Its totient is φ = 10040115288.

The previous prime is 12550144111. The next prime is 12550144163. The reversal of 12550144115 is 51144105521.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51144105521 = 145935054219.

It is a cyclic number.

It is not a de Polignac number, because 12550144115 - 22 = 12550144111 is a prime.

It is a super-2 number, since 2×125501441152 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12550144111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1255014407 + ... + 1255014416.

It is an arithmetic number, because the mean of its divisors is an integer number (3765043236).

Almost surely, 212550144115 is an apocalyptic number.

12550144115 is a deficient number, since it is larger than the sum of its proper divisors (2510028829).

12550144115 is an equidigital number, since it uses as much as digits as its factorization.

12550144115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2510028828.

The product of its (nonzero) digits is 4000, while the sum is 29.

Adding to 12550144115 its reverse (51144105521), we get a palindrome (63694249636).

The spelling of 12550144115 in words is "twelve billion, five hundred fifty million, one hundred forty-four thousand, one hundred fifteen".

Divisors: 1 5 2510028823 12550144115