Base | Representation |
---|---|
bin | 10111011000001111… |
… | …10111110001101011 |
3 | 1012101201201020210202 |
4 | 23230013313301223 |
5 | 201201130433120 |
6 | 5433244302415 |
7 | 623015214146 |
oct | 135407676153 |
9 | 35351636722 |
10 | 12551421035 |
11 | 5360a4a43a |
12 | 2523541a0b |
13 | 1250481a6a |
14 | 870d5b05d |
15 | 4d6d94875 |
hex | 2ec1f7c6b |
12551421035 has 8 divisors (see below), whose sum is σ = 15062457120. Its totient is φ = 10040635584.
The previous prime is 12551421023. The next prime is 12551421041. The reversal of 12551421035 is 53012415521.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12551421035 - 26 = 12551420971 is a prime.
It is a super-3 number, since 3×125514210353 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12551420989 and 12551421007.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75026 + ... + 175304.
It is an arithmetic number, because the mean of its divisors is an integer number (1882807140).
Almost surely, 212551421035 is an apocalyptic number.
12551421035 is a deficient number, since it is larger than the sum of its proper divisors (2511036085).
12551421035 is a wasteful number, since it uses less digits than its factorization.
12551421035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 125317.
The product of its (nonzero) digits is 6000, while the sum is 29.
Adding to 12551421035 its reverse (53012415521), we get a palindrome (65563836556).
The spelling of 12551421035 in words is "twelve billion, five hundred fifty-one million, four hundred twenty-one thousand, thirty-five".
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