12554215140403 has 4 divisors (see below), whose sum is σ = 12554223732360. Its totient is φ = 12554206548448.

The previous prime is 12554215140347. The next prime is 12554215140413. The reversal of 12554215140403 is 30404151245521.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12554215140403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12554215140413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1495873 + ... + 5229346.

It is an arithmetic number, because the mean of its divisors is an integer number (3138555933090).

Almost surely, 2^{12554215140403} is an apocalyptic number.

12554215140403 is a deficient number, since it is larger than the sum of its proper divisors (8591957).

12554215140403 is an equidigital number, since it uses as much as digits as its factorization.

12554215140403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8591956.

The product of its (nonzero) digits is 96000, while the sum is 37.

Adding to 12554215140403 its reverse (30404151245521), we get a palindrome (42958366385924).

The spelling of 12554215140403 in words is "twelve trillion, five hundred fifty-four billion, two hundred fifteen million, one hundred forty thousand, four hundred three".