Base | Representation |
---|---|
bin | 1011011010110011001000… |
… | …1010111110111101000001 |
3 | 1122110020201201002200220212 |
4 | 2312230302022332331001 |
5 | 3121200200433140210 |
6 | 42411411321443505 |
7 | 2434033242633554 |
oct | 266546212767501 |
9 | 48406651080825 |
10 | 12555031146305 |
11 | 4000616855aaa |
12 | 14a92ba640595 |
13 | 700c1ba2290b |
14 | 3159497c069b |
15 | 16b8b9e53805 |
hex | b6b322bef41 |
12555031146305 has 16 divisors (see below), whose sum is σ = 15079291603200. Its totient is φ = 10035191450880.
The previous prime is 12555031146299. The next prime is 12555031146337. The reversal of 12555031146305 is 50364113055521.
It is a de Polignac number, because none of the positive numbers 2k-12555031146305 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37995641 + ... + 38324649.
It is an arithmetic number, because the mean of its divisors is an integer number (942455725200).
Almost surely, 212555031146305 is an apocalyptic number.
It is an amenable number.
12555031146305 is a deficient number, since it is larger than the sum of its proper divisors (2524260456895).
12555031146305 is a wasteful number, since it uses less digits than its factorization.
12555031146305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 335704.
The product of its (nonzero) digits is 270000, while the sum is 41.
The spelling of 12555031146305 in words is "twelve trillion, five hundred fifty-five billion, thirty-one million, one hundred forty-six thousand, three hundred five".
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