Base | Representation |
---|---|
bin | 1011011010110011110011… |
… | …1111010100000011110001 |
3 | 1122110021012100121100112021 |
4 | 2312230330333110003301 |
5 | 3121201033413331101 |
6 | 42411441323431441 |
7 | 2434040605366321 |
oct | 266547477240361 |
9 | 48407170540467 |
10 | 12555212636401 |
11 | 40006aa246216 |
12 | 14a934b385581 |
13 | 700c4a4c8ac6 |
14 | 315965945281 |
15 | 16b8cad535a1 |
hex | b6b3cfd40f1 |
12555212636401 has 4 divisors (see below), whose sum is σ = 12555227607552. Its totient is φ = 12555197665252.
The previous prime is 12555212636399. The next prime is 12555212636431. The reversal of 12555212636401 is 10463621255521.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12555212636401 - 21 = 12555212636399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12555212636431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6147961 + ... + 7931446.
It is an arithmetic number, because the mean of its divisors is an integer number (3138806901888).
Almost surely, 212555212636401 is an apocalyptic number.
It is an amenable number.
12555212636401 is a deficient number, since it is larger than the sum of its proper divisors (14971151).
12555212636401 is an equidigital number, since it uses as much as digits as its factorization.
12555212636401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14971150.
The product of its (nonzero) digits is 432000, while the sum is 43.
The spelling of 12555212636401 in words is "twelve trillion, five hundred fifty-five billion, two hundred twelve million, six hundred thirty-six thousand, four hundred one".
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