Base | Representation |
---|---|
bin | 111010011101110111… |
… | …1110001011001100001 |
3 | 110000002020120112010012 |
4 | 1310323233301121201 |
5 | 4024114421233213 |
6 | 133402502014305 |
7 | 12033256023020 |
oct | 1647357613141 |
9 | 400066515105 |
10 | 125556430433 |
11 | 49280371595 |
12 | 20400717395 |
13 | babc3c8325 |
14 | 611128c8b7 |
15 | 33ecbc04a8 |
hex | 1d3bbf1661 |
125556430433 has 4 divisors (see below), whose sum is σ = 143493063360. Its totient is φ = 107619797508.
The previous prime is 125556430421. The next prime is 125556430529. The reversal of 125556430433 is 334034655521.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334034655521 = 7 ⋅47719236503.
It is a cyclic number.
It is not a de Polignac number, because 125556430433 - 212 = 125556426337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (125556433433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8968316453 + ... + 8968316466.
It is an arithmetic number, because the mean of its divisors is an integer number (35873265840).
Almost surely, 2125556430433 is an apocalyptic number.
It is an amenable number.
125556430433 is a deficient number, since it is larger than the sum of its proper divisors (17936632927).
125556430433 is an equidigital number, since it uses as much as digits as its factorization.
125556430433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17936632926.
The product of its (nonzero) digits is 648000, while the sum is 41.
The spelling of 125556430433 in words is "one hundred twenty-five billion, five hundred fifty-six million, four hundred thirty thousand, four hundred thirty-three".
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