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125565411331 = 605320744327
BaseRepresentation
bin111010011110001001…
…0000010000000000011
3110000002212110210121001
41310330102002000003
54024124221130311
6133403422312431
712033425246263
oct1647422020003
9400085423531
10125565411331
1149285446018
1220403728717
13bac1221079
1461125497a3
1533ed8964c1
hex1d3c482003

125565411331 has 4 divisors (see below), whose sum is σ = 125586161712. Its totient is φ = 125544660952.

The previous prime is 125565411329. The next prime is 125565411383. The reversal of 125565411331 is 133114565521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 125565411331 - 21 = 125565411329 is a prime.

It is a super-2 number, since 2×1255654113312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (125565411311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10366111 + ... + 10378216.

It is an arithmetic number, because the mean of its divisors is an integer number (31396540428).

Almost surely, 2125565411331 is an apocalyptic number.

125565411331 is a deficient number, since it is larger than the sum of its proper divisors (20750381).

125565411331 is an equidigital number, since it uses as much as digits as its factorization.

125565411331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20750380.

The product of its digits is 54000, while the sum is 37.

Adding to 125565411331 its reverse (133114565521), we get a palindrome (258679976852).

The spelling of 125565411331 in words is "one hundred twenty-five billion, five hundred sixty-five million, four hundred eleven thousand, three hundred thirty-one".

Divisors: 1 6053 20744327 125565411331