Base | Representation |
---|---|
bin | 1011011011000101110011… |
… | …0011111110110100101001 |
3 | 1122110201122212222020121220 |
4 | 2312301130303332310221 |
5 | 3121240431111112131 |
6 | 42414000423052253 |
7 | 2434301352160533 |
oct | 266613463766451 |
9 | 48421585866556 |
10 | 12560041504041 |
11 | 4002757a97a19 |
12 | 14aa2785a1089 |
13 | 701539a69b35 |
14 | 315ca2dba853 |
15 | 16baaec53e96 |
hex | b6c5ccfed29 |
12560041504041 has 16 divisors (see below), whose sum is σ = 16760147788800. Its totient is φ = 8366649450768.
The previous prime is 12560041503953. The next prime is 12560041504061. The reversal of 12560041504041 is 14040514006521.
It is not a de Polignac number, because 12560041504041 - 27 = 12560041503913 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12560041503993 and 12560041504011.
It is not an unprimeable number, because it can be changed into a prime (12560041504061) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38525980 + ... + 38850626.
It is an arithmetic number, because the mean of its divisors is an integer number (1047509236800).
Almost surely, 212560041504041 is an apocalyptic number.
It is an amenable number.
12560041504041 is a deficient number, since it is larger than the sum of its proper divisors (4200106284759).
12560041504041 is a wasteful number, since it uses less digits than its factorization.
12560041504041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 334948.
The product of its (nonzero) digits is 19200, while the sum is 33.
The spelling of 12560041504041 in words is "twelve trillion, five hundred sixty billion, forty-one million, five hundred four thousand, forty-one".
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