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12563009483897 = 48712579143807
BaseRepresentation
bin1011011011010000110110…
…1101111011010001111001
31122111000022201202020120202
42312310031231323101321
53121313020411441042
642415211125131545
72434435041452165
oct266641555732171
948430281666522
1012563009483897
114003a40378134
1214aa966559bb5
137018c091ca32
143160a5249ca5
1516bbd55c0632
hexb6d0db7b479

12563009483897 has 4 divisors (see below), whose sum is σ = 12565588632576. Its totient is φ = 12560430335220.

The previous prime is 12563009483839. The next prime is 12563009483951. The reversal of 12563009483897 is 79838490036521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12563009483897 - 214 = 12563009467513 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12563009483597) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1289567033 + ... + 1289576774.

It is an arithmetic number, because the mean of its divisors is an integer number (3141397158144).

It is a 1-persistent number, because it is pandigital, but 2⋅12563009483897 = 25126018967794 is not.

Almost surely, 212563009483897 is an apocalyptic number.

It is an amenable number.

12563009483897 is a deficient number, since it is larger than the sum of its proper divisors (2579148679).

12563009483897 is an equidigital number, since it uses as much as digits as its factorization.

12563009483897 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2579148678.

The product of its (nonzero) digits is 78382080, while the sum is 65.

The spelling of 12563009483897 in words is "twelve trillion, five hundred sixty-three billion, nine million, four hundred eighty-three thousand, eight hundred ninety-seven".

Divisors: 1 4871 2579143807 12563009483897