Base | Representation |
---|---|
bin | 1110111111000… |
… | …00101111111011 |
3 | 22202112021111212 |
4 | 13133200233323 |
5 | 224134413430 |
6 | 20250113335 |
7 | 3054304361 |
oct | 737405773 |
9 | 282467455 |
10 | 125701115 |
11 | 64a56121 |
12 | 3611b84b |
13 | 20071b77 |
14 | 129a1631 |
15 | b07eb95 |
hex | 77e0bfb |
125701115 has 4 divisors (see below), whose sum is σ = 150841344. Its totient is φ = 100560888.
The previous prime is 125701091. The next prime is 125701127. The reversal of 125701115 is 511107521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 125701115 - 216 = 125635579 is a prime.
It is a super-3 number, since 3×1257011153 (a number of 25 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12570107 + ... + 12570116.
It is an arithmetic number, because the mean of its divisors is an integer number (37710336).
Almost surely, 2125701115 is an apocalyptic number.
125701115 is a deficient number, since it is larger than the sum of its proper divisors (25140229).
125701115 is an equidigital number, since it uses as much as digits as its factorization.
125701115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25140228.
The product of its (nonzero) digits is 350, while the sum is 23.
The square root of 125701115 is about 11211.6508597084. The cubic root of 125701115 is about 500.9330776490.
Adding to 125701115 its reverse (511107521), we get a palindrome (636808636).
The spelling of 125701115 in words is "one hundred twenty-five million, seven hundred one thousand, one hundred fifteen".
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