Base | Representation |
---|---|
bin | 1011011101001110011110… |
… | …1101101101101100001001 |
3 | 1122121020100212220212210120 |
4 | 2313103213231231230021 |
5 | 3122341101244214033 |
6 | 42442505243533453 |
7 | 2440040516133006 |
oct | 267234755555411 |
9 | 48536325825716 |
10 | 12596731632393 |
11 | 4017275679447 |
12 | 14b53b7b2a289 |
13 | 704b36191a5c |
14 | 317983b5c8ad |
15 | 16ca0ad881b3 |
hex | b74e7b6db09 |
12596731632393 has 4 divisors (see below), whose sum is σ = 16795642176528. Its totient is φ = 8397821088260.
The previous prime is 12596731632343. The next prime is 12596731632427. The reversal of 12596731632393 is 39323613769521.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12596731632393 - 29 = 12596731631881 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12596731632313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2099455272063 + ... + 2099455272068.
It is an arithmetic number, because the mean of its divisors is an integer number (4198910544132).
Almost surely, 212596731632393 is an apocalyptic number.
It is an amenable number.
12596731632393 is a deficient number, since it is larger than the sum of its proper divisors (4198910544135).
12596731632393 is an equidigital number, since it uses as much as digits as its factorization.
12596731632393 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4198910544134.
The product of its digits is 33067440, while the sum is 60.
The spelling of 12596731632393 in words is "twelve trillion, five hundred ninety-six billion, seven hundred thirty-one million, six hundred thirty-two thousand, three hundred ninety-three".
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