125989440953 has 4 divisors (see below), whose sum is σ = 125995397520. Its totient is φ = 125983484388.

The previous prime is 125989440947. The next prime is 125989440959. The reversal of 125989440953 is 359044989521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (125989440947) and next prime (125989440959).

It is a cyclic number.

It is not a de Polignac number, because 125989440953 - 2⁸ = 125989440697 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125989440892 and 125989440901.

It is not an unprimeable number, because it can be changed into a prime (125989440959) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2946443 + ... + 2988896.

It is an arithmetic number, because the mean of its divisors is an integer number (31498849380).

Almost surely, 2^125989440953 is an apocalyptic number.

It is an amenable number.

125989440953 is a deficient number, since it is larger than the sum of its proper divisors (5956567).

125989440953 is an equidigital number, since it uses as much as digits as its factorization.

125989440953 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5956566.

The product of its (nonzero) digits is 13996800, while the sum is 59.

The spelling of 125989440953 in words is "one hundred twenty-five billion, nine hundred eighty-nine million, four hundred forty thousand, nine hundred fifty-three".