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12603641233 = 38803324811
BaseRepresentation
bin10111011110011110…
…00100110110010001
31012112100222022110011
423233033010312101
5201303013004413
65442351434521
7624221116501
oct135717046621
935470868404
1012603641233
115388477227
122538b25a41
13125b2368a1
14877c71a01
154db75c33d
hex2ef3c4d91

12603641233 has 4 divisors (see below), whose sum is σ = 12604004848. Its totient is φ = 12603277620.

The previous prime is 12603641161. The next prime is 12603641243. The reversal of 12603641233 is 33214630621.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12603641233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12603641195 and 12603641204.

It is not an unprimeable number, because it can be changed into a prime (12603641243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123603 + ... + 201208.

It is an arithmetic number, because the mean of its divisors is an integer number (3151001212).

Almost surely, 212603641233 is an apocalyptic number.

It is an amenable number.

12603641233 is a deficient number, since it is larger than the sum of its proper divisors (363615).

12603641233 is an equidigital number, since it uses as much as digits as its factorization.

12603641233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 363614.

The product of its (nonzero) digits is 15552, while the sum is 31.

The spelling of 12603641233 in words is "twelve billion, six hundred three million, six hundred forty-one thousand, two hundred thirty-three".

Divisors: 1 38803 324811 12603641233