12604781353 has 4 divisors (see below), whose sum is σ = 12605034240. Its totient is φ = 12604528468.

The previous prime is 12604781351. The next prime is 12604781389. The reversal of 12604781353 is 35318740621.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35318740621 = 71 ⋅497447051.

It is a cyclic number.

It is not a de Polignac number, because 12604781353 - 2¹ = 12604781351 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12604781351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24025 + ... + 160582.

It is an arithmetic number, because the mean of its divisors is an integer number (3151258560).

Almost surely, 2^12604781353 is an apocalyptic number.

It is an amenable number.

12604781353 is a deficient number, since it is larger than the sum of its proper divisors (252887).

12604781353 is an equidigital number, since it uses as much as digits as its factorization.

12604781353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 252886.

The product of its (nonzero) digits is 120960, while the sum is 40.

The spelling of 12604781353 in words is "twelve billion, six hundred four million, seven hundred eighty-one thousand, three hundred fifty-three".