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12606717113 = 19663511427
BaseRepresentation
bin10111011110110101…
…10011110010111001
31012112120202120202122
423233122303302321
5201304304421423
65442541411025
7624256220204
oct135732636271
935476676678
1012606717113
11538a188181
122539b69a75
13125ba72933
1487843293b
154dbb688c8
hex2ef6b3cb9

12606717113 has 4 divisors (see below), whose sum is σ = 13270228560. Its totient is φ = 11943205668.

The previous prime is 12606717061. The next prime is 12606717127. The reversal of 12606717113 is 31171760621.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31171760621 = 226211378001.

It is not a de Polignac number, because 12606717113 - 224 = 12589939897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12606717133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 331755695 + ... + 331755732.

It is an arithmetic number, because the mean of its divisors is an integer number (3317557140).

Almost surely, 212606717113 is an apocalyptic number.

It is an amenable number.

12606717113 is a deficient number, since it is larger than the sum of its proper divisors (663511447).

12606717113 is an equidigital number, since it uses as much as digits as its factorization.

12606717113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 663511446.

The product of its (nonzero) digits is 10584, while the sum is 35.

The spelling of 12606717113 in words is "twelve billion, six hundred six million, seven hundred seventeen thousand, one hundred thirteen".

Divisors: 1 19 663511427 12606717113