Base | Representation |
---|---|
bin | 1011011111110010101010… |
… | …1010110110101110111001 |
3 | 1122202110010102001002212021 |
4 | 2313330222222312232321 |
5 | 3124101331441120213 |
6 | 42515034441114441 |
7 | 2443160631335521 |
oct | 267745252665671 |
9 | 48673112032767 |
10 | 12640804629433 |
11 | 4033a31739442 |
12 | 1501a57a88a21 |
13 | 70903b013726 |
14 | 319b65242681 |
15 | 16dc3a213d8d |
hex | b7f2aab6bb9 |
12640804629433 has 4 divisors (see below), whose sum is σ = 12818844131328. Its totient is φ = 12462765127540.
The previous prime is 12640804629413. The next prime is 12640804629437. The reversal of 12640804629433 is 33492640804621.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12640804629433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12640804629437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89019750841 + ... + 89019750982.
It is an arithmetic number, because the mean of its divisors is an integer number (3204711032832).
Almost surely, 212640804629433 is an apocalyptic number.
It is an amenable number.
12640804629433 is a deficient number, since it is larger than the sum of its proper divisors (178039501895).
12640804629433 is an equidigital number, since it uses as much as digits as its factorization.
12640804629433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 178039501894.
The product of its (nonzero) digits is 5971968, while the sum is 52.
The spelling of 12640804629433 in words is "twelve trillion, six hundred forty billion, eight hundred four million, six hundred twenty-nine thousand, four hundred thirty-three".
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