Base | Representation |
---|---|
bin | 10111100010111111… |
… | …00000110000000001 |
3 | 1012122000012221202101 |
4 | 23301133200300001 |
5 | 201342211114012 |
6 | 5450223150401 |
7 | 625161004354 |
oct | 136137406001 |
9 | 35560187671 |
10 | 12641504257 |
11 | 53a7888288 |
12 | 2549745401 |
13 | 1266032845 |
14 | 87ccca29b |
15 | 4dec3ad57 |
hex | 2f17e0c01 |
12641504257 has 4 divisors (see below), whose sum is σ = 12648233920. Its totient is φ = 12634774596.
The previous prime is 12641504233. The next prime is 12641504273. The reversal of 12641504257 is 75240514621.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 75240514621 = 2357 ⋅31922153.
It is a cyclic number.
It is not a de Polignac number, because 12641504257 - 231 = 10494020609 is a prime.
It is a super-3 number, since 3×126415042573 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12641504357) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3362013 + ... + 3365770.
It is an arithmetic number, because the mean of its divisors is an integer number (3162058480).
Almost surely, 212641504257 is an apocalyptic number.
It is an amenable number.
12641504257 is a deficient number, since it is larger than the sum of its proper divisors (6729663).
12641504257 is an equidigital number, since it uses as much as digits as its factorization.
12641504257 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6729662.
The product of its (nonzero) digits is 67200, while the sum is 37.
The spelling of 12641504257 in words is "twelve billion, six hundred forty-one million, five hundred four thousand, two hundred fifty-seven".
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