Base | Representation |
---|---|
bin | 1011100000000101000001… |
… | …1011001011010110111001 |
3 | 1122202220211212200100021110 |
4 | 2320001100123023112321 |
5 | 3124141430123133423 |
6 | 42521211453430533 |
7 | 2443424024100423 |
oct | 270012033132671 |
9 | 48686755610243 |
10 | 12645733021113 |
11 | 4036030687015 |
12 | 15029b249b449 |
13 | 70964508c71a |
14 | 31a0b19c3813 |
15 | 16de27c23193 |
hex | b80506cb5b9 |
12645733021113 has 8 divisors (see below), whose sum is σ = 16861074976800. Its totient is φ = 8430439873088.
The previous prime is 12645733021087. The next prime is 12645733021147. The reversal of 12645733021113 is 31112033754621.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12645733021113 - 221 = 12645730923961 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12645733021013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11593023 + ... + 12636836.
It is an arithmetic number, because the mean of its divisors is an integer number (2107634372100).
Almost surely, 212645733021113 is an apocalyptic number.
It is an amenable number.
12645733021113 is a deficient number, since it is larger than the sum of its proper divisors (4215341955687).
12645733021113 is a wasteful number, since it uses less digits than its factorization.
12645733021113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24403831.
The product of its (nonzero) digits is 90720, while the sum is 39.
Adding to 12645733021113 its reverse (31112033754621), we get a palindrome (43757766775734).
The spelling of 12645733021113 in words is "twelve trillion, six hundred forty-five billion, seven hundred thirty-three million, twenty-one thousand, one hundred thirteen".
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