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12649403 = 13973031
BaseRepresentation
bin110000010000…
…001110111011
3212210122201102
4300100032323
511214240103
61131042015
7212342504
oct60201673
925718642
1012649403
11715a758
1242a030b
13280b770
141973bab
15119ce88
hexc103bb

12649403 has 4 divisors (see below), whose sum is σ = 13622448. Its totient is φ = 11676360.

The previous prime is 12649391. The next prime is 12649409. The reversal of 12649403 is 30494621.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12649403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12649409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 486503 + ... + 486528.

It is an arithmetic number, because the mean of its divisors is an integer number (3405612).

Almost surely, 212649403 is an apocalyptic number.

12649403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12649403 is a deficient number, since it is larger than the sum of its proper divisors (973045).

12649403 is an equidigital number, since it uses as much as digits as its factorization.

12649403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 973044.

The product of its (nonzero) digits is 5184, while the sum is 29.

The square root of 12649403 is about 3556.5999212731. The cubic root of 12649403 is about 233.0004052379. Note that the first 3 decimals are identical.

The spelling of 12649403 in words is "twelve million, six hundred forty-nine thousand, four hundred three".

Divisors: 1 13 973031 12649403