Base | Representation |
---|---|
bin | 111011000010001010… |
… | …1010011110110100001 |
3 | 110010020010002011122220 |
4 | 1312010111103312201 |
5 | 4034113200333213 |
6 | 134123403421253 |
7 | 12105404115234 |
oct | 1660425236641 |
9 | 403203064586 |
10 | 126774230433 |
11 | 49845825774 |
12 | 206a0524829 |
13 | bc547b2746 |
14 | 61c8cd341b |
15 | 346ea74e23 |
hex | 1d84553da1 |
126774230433 has 4 divisors (see below), whose sum is σ = 169032307248. Its totient is φ = 84516153620.
The previous prime is 126774230419. The next prime is 126774230447. The reversal of 126774230433 is 334032477621.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (126774230419) and next prime (126774230447).
It is a cyclic number.
It is not a de Polignac number, because 126774230433 - 29 = 126774229921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (126774230483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21129038403 + ... + 21129038408.
It is an arithmetic number, because the mean of its divisors is an integer number (42258076812).
Almost surely, 2126774230433 is an apocalyptic number.
It is an amenable number.
126774230433 is a deficient number, since it is larger than the sum of its proper divisors (42258076815).
126774230433 is an equidigital number, since it uses as much as digits as its factorization.
126774230433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42258076814.
The product of its (nonzero) digits is 508032, while the sum is 42.
The spelling of 126774230433 in words is "one hundred twenty-six billion, seven hundred seventy-four million, two hundred thirty thousand, four hundred thirty-three".
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