Base | Representation |
---|---|
bin | 111011001000110110… |
… | …0110001100010010011 |
3 | 110010210202001111021202 |
4 | 1312101230301202103 |
5 | 4040043103011024 |
6 | 134201534141415 |
7 | 12114066212111 |
oct | 1662154614223 |
9 | 403722044252 |
10 | 126998485139 |
11 | 49950374639 |
12 | 2074365186b |
13 | bc8c0ac936 |
14 | 620a9caab1 |
15 | 34845c0bae |
hex | 1d91b31893 |
126998485139 has 4 divisors (see below), whose sum is σ = 126999309360. Its totient is φ = 126997660920.
The previous prime is 126998485129. The next prime is 126998485147. The reversal of 126998485139 is 931584899621.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 931584899621 = 211 ⋅4415094311.
It is a cyclic number.
It is not a de Polignac number, because 126998485139 - 28 = 126998484883 is a prime.
It is a super-2 number, since 2×1269984851392 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (126998485129) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104399 + ... + 514680.
It is an arithmetic number, because the mean of its divisors is an integer number (31749827340).
Almost surely, 2126998485139 is an apocalyptic number.
126998485139 is a deficient number, since it is larger than the sum of its proper divisors (824221).
126998485139 is an equidigital number, since it uses as much as digits as its factorization.
126998485139 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 824220.
The product of its digits is 33592320, while the sum is 65.
The spelling of 126998485139 in words is "one hundred twenty-six billion, nine hundred ninety-eight million, four hundred eighty-five thousand, one hundred thirty-nine".
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