Base | Representation |
---|---|
bin | 10111101011101011… |
… | …00101001100011011 |
3 | 1012211002101100211211 |
4 | 23311311211030123 |
5 | 202014341222431 |
6 | 5501345403551 |
7 | 630034414114 |
oct | 136565451433 |
9 | 35732340754 |
10 | 12714398491 |
11 | 5434a45853 |
12 | 256a0395b7 |
13 | 1278175822 |
14 | 88886320b |
15 | 4e63392b1 |
hex | 2f5d6531b |
12714398491 has 4 divisors (see below), whose sum is σ = 12726707752. Its totient is φ = 12702089232.
The previous prime is 12714398479. The next prime is 12714398503. The reversal of 12714398491 is 19489341721.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 19489341721 = 1993 ⋅9778897.
It is an interprime number because it is at equal distance from previous prime (12714398479) and next prime (12714398503).
It is a cyclic number.
It is not a de Polignac number, because 12714398491 - 231 = 10566914843 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12714398591) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6153081 + ... + 6155146.
It is an arithmetic number, because the mean of its divisors is an integer number (3181676938).
Almost surely, 212714398491 is an apocalyptic number.
12714398491 is a deficient number, since it is larger than the sum of its proper divisors (12309261).
12714398491 is a wasteful number, since it uses less digits than its factorization.
12714398491 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12309260.
The product of its digits is 435456, while the sum is 49.
The spelling of 12714398491 in words is "twelve billion, seven hundred fourteen million, three hundred ninety-eight thousand, four hundred ninety-one".
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