Base | Representation |
---|---|
bin | 1011100100100000001001… |
… | …1101100011001010101011 |
3 | 1200001012000112202000101020 |
4 | 2321020002131203022223 |
5 | 3131413103003301103 |
6 | 43020141211423523 |
7 | 2452054303321164 |
oct | 271100235431253 |
9 | 50035015660336 |
10 | 12721734431403 |
11 | 40652914824a8 |
12 | 1515683154ba3 |
13 | 713867977a0a |
14 | 31da4169476b |
15 | 170dc5149753 |
hex | b92027632ab |
12721734431403 has 4 divisors (see below), whose sum is σ = 16962312575208. Its totient is φ = 8481156287600.
The previous prime is 12721734431353. The next prime is 12721734431411. The reversal of 12721734431403 is 30413443712721.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12721734431403 is a prime.
It is a super-2 number, since 2×127217344314032 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12721734431423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2120289071898 + ... + 2120289071903.
It is an arithmetic number, because the mean of its divisors is an integer number (4240578143802).
Almost surely, 212721734431403 is an apocalyptic number.
12721734431403 is a deficient number, since it is larger than the sum of its proper divisors (4240578143805).
12721734431403 is an equidigital number, since it uses as much as digits as its factorization.
12721734431403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4240578143804.
The product of its (nonzero) digits is 338688, while the sum is 42.
The spelling of 12721734431403 in words is "twelve trillion, seven hundred twenty-one billion, seven hundred thirty-four million, four hundred thirty-one thousand, four hundred three".
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