Search a number
-
+
127344099457 = 151843338407
BaseRepresentation
bin111011010011001001…
…1001100000010000001
3110011200211101112000001
41312212103030002001
54041300042140312
6134300122000001
712125463662041
oct1664623140201
9404624345001
10127344099457
114a008473803
122081b346001
13c01588b853
146240875721
1534a4ae0057
hex1da64cc081

127344099457 has 4 divisors (see below), whose sum is σ = 128187438016. Its totient is φ = 126500760900.

The previous prime is 127344099433. The next prime is 127344099461. The reversal of 127344099457 is 754990443721.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 754990443721 = 1043837232887.

It is a cyclic number.

It is not a de Polignac number, because 127344099457 - 219 = 127343575169 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 127344099398 and 127344099407.

It is not an unprimeable number, because it can be changed into a prime (127344099257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 421669053 + ... + 421669354.

It is an arithmetic number, because the mean of its divisors is an integer number (32046859504).

Almost surely, 2127344099457 is an apocalyptic number.

It is an amenable number.

127344099457 is a deficient number, since it is larger than the sum of its proper divisors (843338559).

127344099457 is an equidigital number, since it uses as much as digits as its factorization.

127344099457 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 843338558.

The product of its (nonzero) digits is 7620480, while the sum is 55.

The spelling of 127344099457 in words is "one hundred twenty-seven billion, three hundred forty-four million, ninety-nine thousand, four hundred fifty-seven".

Divisors: 1 151 843338407 127344099457