Base | Representation |
---|---|
bin | 10111101110110110… |
… | …11111000101010011 |
3 | 1012212221122120002111 |
4 | 23313123133011103 |
5 | 202043211042042 |
6 | 5504142130151 |
7 | 630510444361 |
oct | 136733370523 |
9 | 35787576074 |
10 | 12741112147 |
11 | 5449031155 |
12 | 2576b80957 |
13 | 1280869a1a |
14 | 88c218631 |
15 | 4e8864517 |
hex | 2f76df153 |
12741112147 has 4 divisors (see below), whose sum is σ = 12772885896. Its totient is φ = 12709338400.
The previous prime is 12741112141. The next prime is 12741112157. The reversal of 12741112147 is 74121114721.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12741112147 - 223 = 12732723539 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12741112141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15886273 + ... + 15887074.
It is an arithmetic number, because the mean of its divisors is an integer number (3193221474).
Almost surely, 212741112147 is an apocalyptic number.
12741112147 is a deficient number, since it is larger than the sum of its proper divisors (31773749).
12741112147 is an equidigital number, since it uses as much as digits as its factorization.
12741112147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31773748.
The product of its digits is 3136, while the sum is 31.
Adding to 12741112147 its reverse (74121114721), we get a palindrome (86862226868).
The spelling of 12741112147 in words is "twelve billion, seven hundred forty-one million, one hundred twelve thousand, one hundred forty-seven".
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