12749243803 has 4 divisors (see below), whose sum is σ = 12760930728. Its totient is φ = 12737556880.

The previous prime is 12749243779. The next prime is 12749243839. The reversal of 12749243803 is 30834294721.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12749243803 - 2²⁹ = 12212372891 is a prime.

It is a super-3 number, since 3×12749243803³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12749243803.

It is not an unprimeable number, because it can be changed into a prime (12749243203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5841826 + ... + 5844007.

It is an arithmetic number, because the mean of its divisors is an integer number (3190232682).

Almost surely, 2^12749243803 is an apocalyptic number.

12749243803 is a deficient number, since it is larger than the sum of its proper divisors (11686925).

12749243803 is a wasteful number, since it uses less digits than its factorization.

12749243803 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11686924.

The product of its (nonzero) digits is 290304, while the sum is 43.

The spelling of 12749243803 in words is "twelve billion, seven hundred forty-nine million, two hundred forty-three thousand, eight hundred three".