Base | Representation |
---|---|
bin | 10111110001110110… |
… | …11110011101001011 |
3 | 1012221200222222120221 |
4 | 23320323132131023 |
5 | 202121131303103 |
6 | 5510441330511 |
7 | 631234356550 |
oct | 137073363513 |
9 | 35850888527 |
10 | 12766275403 |
11 | 5461258732 |
12 | 2583496a37 |
13 | 1285b3a31b |
14 | 8916c8a27 |
15 | 4eab851bd |
hex | 2f8ede74b |
12766275403 has 4 divisors (see below), whose sum is σ = 14590029040. Its totient is φ = 10942521768.
The previous prime is 12766275371. The next prime is 12766275463. The reversal of 12766275403 is 30457266721.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30457266721 = 7 ⋅4351038103.
It is a cyclic number.
It is not a de Polignac number, because 12766275403 - 25 = 12766275371 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12766275403.
It is not an unprimeable number, because it can be changed into a prime (12766275463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 911876808 + ... + 911876821.
It is an arithmetic number, because the mean of its divisors is an integer number (3647507260).
Almost surely, 212766275403 is an apocalyptic number.
12766275403 is a deficient number, since it is larger than the sum of its proper divisors (1823753637).
12766275403 is an equidigital number, since it uses as much as digits as its factorization.
12766275403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1823753636.
The product of its (nonzero) digits is 423360, while the sum is 43.
The spelling of 12766275403 in words is "twelve billion, seven hundred sixty-six million, two hundred seventy-five thousand, four hundred three".
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