Base | Representation |
---|---|
bin | 10010101010111011111… |
… | …101001011011001000011 |
3 | 11112122210012202201021110 |
4 | 102222323331023121003 |
5 | 132010143212143133 |
6 | 2421232100054403 |
7 | 161461156630032 |
oct | 22527375133103 |
9 | 4478705681243 |
10 | 1283053631043 |
11 | 45515a364398 |
12 | 1887b8094403 |
13 | 93cb72610a2 |
14 | 46158a6a719 |
15 | 235962e3c63 |
hex | 12abbf4b643 |
1283053631043 has 4 divisors (see below), whose sum is σ = 1710738174728. Its totient is φ = 855369087360.
The previous prime is 1283053631011. The next prime is 1283053631071. The reversal of 1283053631043 is 3401363503821.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1283053631043 - 25 = 1283053631011 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1283053630992 and 1283053631010.
It is not an unprimeable number, because it can be changed into a prime (1283053631003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213842271838 + ... + 213842271843.
It is an arithmetic number, because the mean of its divisors is an integer number (427684543682).
Almost surely, 21283053631043 is an apocalyptic number.
1283053631043 is a deficient number, since it is larger than the sum of its proper divisors (427684543685).
1283053631043 is an equidigital number, since it uses as much as digits as its factorization.
1283053631043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 427684543684.
The product of its (nonzero) digits is 155520, while the sum is 39.
The spelling of 1283053631043 in words is "one trillion, two hundred eighty-three billion, fifty-three million, six hundred thirty-one thousand, forty-three".
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