Base | Representation |
---|---|
bin | 111011110010001001… |
… | …0001010111010010001 |
3 | 110021101022011221221220 |
4 | 1313210102022322101 |
5 | 4100412302120423 |
6 | 134551231035253 |
7 | 12163322110506 |
oct | 1674422127221 |
9 | 407338157856 |
10 | 128384020113 |
11 | 4a4a1483568 |
12 | 20a6b66bb29 |
13 | c15016540b |
14 | 62dca154ad |
15 | 35160599e3 |
hex | 1de448ae91 |
128384020113 has 4 divisors (see below), whose sum is σ = 171178693488. Its totient is φ = 85589346740.
The previous prime is 128384020069. The next prime is 128384020117. The reversal of 128384020113 is 311020483821.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 128384020113 - 221 = 128381922961 is a prime.
It is not an unprimeable number, because it can be changed into a prime (128384020117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21397336683 + ... + 21397336688.
It is an arithmetic number, because the mean of its divisors is an integer number (42794673372).
Almost surely, 2128384020113 is an apocalyptic number.
It is an amenable number.
128384020113 is a deficient number, since it is larger than the sum of its proper divisors (42794673375).
128384020113 is an equidigital number, since it uses as much as digits as its factorization.
128384020113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42794673374.
The product of its (nonzero) digits is 9216, while the sum is 33.
The spelling of 128384020113 in words is "one hundred twenty-eight billion, three hundred eighty-four million, twenty thousand, one hundred thirteen".
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