Base | Representation |
---|---|
bin | 10111111011010011… |
… | …01010111011110011 |
3 | 1020011020001201002011 |
4 | 23331221222323303 |
5 | 202301421302003 |
6 | 5522351303351 |
7 | 633215616556 |
oct | 137551527363 |
9 | 36136051064 |
10 | 12845494003 |
11 | 54a1a45851 |
12 | 25a5b1ab57 |
13 | 1299385b34 |
14 | 89c02a69d |
15 | 502ad246d |
hex | 2fda6aef3 |
12845494003 has 4 divisors (see below), whose sum is σ = 12846100888. Its totient is φ = 12844887120.
The previous prime is 12845493923. The next prime is 12845494033. The reversal of 12845494003 is 30049454821.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12845494003 - 217 = 12845362931 is a prime.
It is a super-2 number, since 2×128454940032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12845494033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 270501 + ... + 314422.
It is an arithmetic number, because the mean of its divisors is an integer number (3211525222).
Almost surely, 212845494003 is an apocalyptic number.
12845494003 is a deficient number, since it is larger than the sum of its proper divisors (606885).
12845494003 is an equidigital number, since it uses as much as digits as its factorization.
12845494003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 606884.
The product of its (nonzero) digits is 138240, while the sum is 40.
The spelling of 12845494003 in words is "twelve billion, eight hundred forty-five million, four hundred ninety-four thousand, three".
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