12855301114041 has 135 divisors (see below), whose sum is σ = 20238278026527. Its totient is φ = 8131752972000.

The previous prime is 12855301114031. The next prime is 12855301114091. The reversal of 12855301114041 is 14041110355821.

The square root of 12855301114041 is 3585429.

It is a perfect power (a square), and thus also a powerful number.

12855301114041 is a `hidden beast` number, since 1 + 2 + 8 + 5 + 530 + 1 + 114 + 0 + 4 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 141655129641 + 12713645984400 = 376371^2 + 3565620^2 .

It is not a de Polignac number, because 12855301114041 - 2¹¹ = 12855301111993 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12855301113987 and 12855301114005.

It is not an unprimeable number, because it can be changed into a prime (12855301114031) by changing a digit.

It is a polite number, since it can be written in 134 ways as a sum of consecutive naturals, for example, 71023762971 + ... + 71023763151.

Almost surely, 2^{12855301114041} is an apocalyptic number.

12855301114041 is the 3585429-th square number.

12855301114041 is the 1792715-th centered octagonal number.

It is an amenable number.

12855301114041 is a deficient number, since it is larger than the sum of its proper divisors (7382976912486).

12855301114041 is an frugal number, since it uses more digits than its factorization.

12855301114041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 578 (or 286 counting only the distinct ones).

The product of its (nonzero) digits is 19200, while the sum is 36.

Multiplying 12855301114041 by its sum of digits (36), we get a square (462790840105476 = 21512574²).

Adding to 12855301114041 its reverse (14041110355821), we get a palindrome (26896411469862).

The spelling of 12855301114041 in words is "twelve trillion, eight hundred fifty-five billion, three hundred one million, one hundred fourteen thousand, forty-one".