Base | Representation |
---|---|
bin | 10010110000011010000… |
… | …010011010001110110011 |
3 | 11120012221112121012102112 |
4 | 102300122002122032303 |
5 | 132104210304400042 |
6 | 2424042551235535 |
7 | 162056545653533 |
oct | 22603202321663 |
9 | 4505845535375 |
10 | 1288927028147 |
11 | 4576a3783590 |
12 | 189977078bab |
13 | 947120306a5 |
14 | 46554b214c3 |
15 | 237dbc6e982 |
hex | 12c1a09a3b3 |
1288927028147 has 4 divisors (see below), whose sum is σ = 1406102212536. Its totient is φ = 1171751843760.
The previous prime is 1288927028131. The next prime is 1288927028177. The reversal of 1288927028147 is 7418207298821.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1288927028147 - 24 = 1288927028131 is a prime.
It is a super-2 number, since 2×12889270281472 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1288927028177) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58587592178 + ... + 58587592199.
It is an arithmetic number, because the mean of its divisors is an integer number (351525553134).
Almost surely, 21288927028147 is an apocalyptic number.
1288927028147 is a deficient number, since it is larger than the sum of its proper divisors (117175184389).
1288927028147 is a wasteful number, since it uses less digits than its factorization.
1288927028147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117175184388.
The product of its (nonzero) digits is 7225344, while the sum is 59.
The spelling of 1288927028147 in words is "one trillion, two hundred eighty-eight billion, nine hundred twenty-seven million, twenty-eight thousand, one hundred forty-seven".
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